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Popular Calculus >

integral from 0 to 1 of-x^2+1

Solution

\int_{0}^{1} - x^{2} + 1 d x

Solution

\frac{2}{3}

+1

Decimal

0.66666 \dots

Solution steps

\int_{0}^{1} - x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{1} x^{2} d x + \int_{0}^{1} 1 d x

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} 1 d x = 1

= - \frac{1}{3} + 1

Simplify

- \frac{1}{3} + 1 : \frac{2}{3}

= \frac{2}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of-x^2+1 ?
The integral from 0 to 1 of-x^2+1 is 2/3