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Popular Calculus >

integral from 1 to 4 of (x+2)

Solution

\int_{1}^{4} (x + 2) d x

Solution

\frac{27}{2}

+1

Decimal

13.5

Solution steps

\int_{1}^{4} x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x d x + \int_{1}^{4} 2 d x

\int_{1}^{4} x d x = \frac{15}{2}

\int_{1}^{4} 2 d x = 6

= \frac{15}{2} + 6

Simplify

\frac{15}{2} + 6 : \frac{27}{2}

= \frac{27}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of (x+2) ?
The integral from 1 to 4 of (x+2) is 27/2