integral from-3 to 0 of-sqrt(9-x^2)

Lösung

\int_{- 3}^{0} - 9 - x^{2} d x

- \frac{9 π}{4}

Dezimale

- 7.06858 \dots

Schritte zur Lösung

\int_{- 3}^{0} - 9 - x^{2} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{- 3}^{0} 9 - x^{2} d x

Trigonometrische Substitution anwenden

= - \int_{- \frac{π}{2}}^{0} 9 cos^{2} (u) d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 9 \cdot \int_{- \frac{π}{2}}^{0} cos^{2} (u) d u

Umschreiben mit Hilfe von Trigonometrie-Identitäten

= - 9 \cdot \int_{- \frac{π}{2}}^{0} \frac{1 + cos ( 2 u )}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 9 \cdot \frac{1}{2} \cdot \int_{- \frac{π}{2}}^{0} 1 + cos (2 u) d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - 9 \cdot \frac{1}{2} (\int_{- \frac{π}{2}}^{0} 1 d u + \int_{- \frac{π}{2}}^{0} cos (2 u) d u)

\int_{- \frac{π}{2}}^{0} 1 d u = \frac{π}{2}

\int_{- \frac{π}{2}}^{0} cos (2 u) d u = 0

= - 9 \cdot \frac{1}{2} (\frac{π}{2} + 0)

Vereinfache

- 9 \cdot \frac{1}{2} (\frac{π}{2} + 0) : - \frac{9 π}{4}

= - \frac{9 π}{4}

\int_{0}^{3} x^{3} e^{2 x} d x

\int_{0}^{2} x sin (x) d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} cos^{5} (x) d x

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\int_{0}^{\frac{π}{2}} cos (n x) d x