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Popular Calculus >

integral from-1 to 2 of (x^3+x)

Solution

\int_{- 1}^{2} (x^{3} + x) d x

Solution

\frac{21}{4}

+1

Decimal

5.25

Solution steps

\int_{- 1}^{2} x^{3} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{3} d x + \int_{- 1}^{2} x d x

\int_{- 1}^{2} x^{3} d x = \frac{15}{4}

\int_{- 1}^{2} x d x = \frac{3}{2}

= \frac{15}{4} + \frac{3}{2}

Simplify

\frac{15}{4} + \frac{3}{2} : \frac{21}{4}

= \frac{21}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of (x^3+x) ?
The integral from-1 to 2 of (x^3+x) is 21/4