What is the integral from 1 to 2 of 3^x ?

The integral from 1 to 2 of 3^x is 6/(ln(3))

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integral from 1 to 2 of 3^x

\int_{1}^{2} 3^{x} d x

\frac{6}{ln ( 3 )}

Decimal

5.46143 \dots

Solution steps

\int_{1}^{2} 3^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{3 ^{x}}{ln ( 3 )}]_{1}^{2}

Compute the boundaries:

\frac{6}{ln ( 3 )}

= \frac{6}{ln ( 3 )}

What is the integral from 1 to 2 of 3^x ?
The integral from 1 to 2 of 3^x is 6/(ln(3))