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Popular Calculus >

integral from 1 to 4 of (x+1)

Solution

\int_{1}^{4} (x + 1) d x

Solution

\frac{21}{2}

+1

Decimal

10.5

Solution steps

\int_{1}^{4} x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x d x + \int_{1}^{4} 1 d x

\int_{1}^{4} x d x = \frac{15}{2}

\int_{1}^{4} 1 d x = 3

= \frac{15}{2} + 3

Simplify

\frac{15}{2} + 3 : \frac{21}{2}

= \frac{21}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of (x+1) ?
The integral from 1 to 4 of (x+1) is 21/2