What is the integral from 1 to 4 of z(1-1/e) ?

The integral from 1 to 4 of z(1-1/e) is (15(e-1))/(2e)

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integral from 1 to 4 of z(1-1/e)

\int_{1}^{4} z (1 - \frac{1}{e}) d z

\frac{15 ( e - 1 )}{2 e}

Decimal

4.74090 \dots

Solution steps

\int_{1}^{4} z (1 - \frac{1}{e}) d z

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= (1 - \frac{1}{e}) \cdot \int_{1}^{4} z d z

\int_{1}^{4} z d z = \frac{15}{2}

= (1 - \frac{1}{e}) \frac{15}{2}

Simplify

(1 - \frac{1}{e}) \frac{15}{2} : \frac{15 ( e - 1 )}{2 e}

= \frac{15 ( e - 1 )}{2 e}

What is the integral from 1 to 4 of z(1-1/e) ?
The integral from 1 to 4 of z(1-1/e) is (15(e-1))/(2e)