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Popular Calculus >

integral from-3 to 1 of |x+2|

Solution

\int_{- 3}^{1} ∣ x + 2 ∣ d x

Solution

5

Solution steps

\int_{- 3}^{1} ∣ x + 2 ∣ d x

Eliminate Absolutes

= \int_{- 3}^{- 2} - x - 2 d x + \int_{- 2}^{1} x + 2 d x

\int_{- 3}^{- 2} - x - 2 d x = \frac{1}{2}

\int_{- 2}^{1} x + 2 d x = \frac{9}{2}

= \frac{1}{2} + \frac{9}{2}

Simplify

\frac{1}{2} + \frac{9}{2} : 5

= 5

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-3 to 1 of |x+2| ?
The integral from-3 to 1 of |x+2| is 5