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Popular Calculus >

integral from-2 to 0 of x^2+x

Solution

\int_{- 2}^{0} x^{2} + x d x

Solution

\frac{2}{3}

+1

Decimal

0.66666 \dots

Solution steps

\int_{- 2}^{0} x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{0} x^{2} d x + \int_{- 2}^{0} x d x

\int_{- 2}^{0} x^{2} d x = \frac{8}{3}

\int_{- 2}^{0} x d x = - 2

= \frac{8}{3} - 2

Simplify

\frac{8}{3} - 2 : \frac{2}{3}

= \frac{2}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-2 to 0 of x^2+x ?
The integral from-2 to 0 of x^2+x is 2/3