What is the integral from 0 to ln(5) of 2e^{3x} ?

The integral from 0 to ln(5) of 2e^{3x} is 248/3

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integral from 0 to ln(5) of 2e^{3x}

\int_{0}^{l n (5)} 2 e^{3 x} d x

\frac{248}{3}

Decimal

82.66666 \dots

Solution steps

\int_{0}^{l n (5)} 2 e^{3 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{l n (5)} e^{3 x} d x

Apply u-substitution

= 2 \cdot \int_{0}^{3 l n (5)} e^{u} \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{3} \cdot \int_{0}^{3 l n (5)} e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 2 \cdot \frac{1}{3} [e^{u}]_{0}^{3 l n (5)}

Simplify

2 \cdot \frac{1}{3} [e^{u}]_{0}^{3 l n (5)} : \frac{2}{3} [e^{u}]_{0}^{3 l n (5)}

= \frac{2}{3} [e^{u}]_{0}^{3 l n (5)}

Compute the boundaries:

124

= \frac{2}{3} \cdot 124

Simplify

= \frac{248}{3}

What is the integral from 0 to ln(5) of 2e^{3x} ?
The integral from 0 to ln(5) of 2e^{3x} is 248/3