What is the integral from 1 to x^2 of (sin(x))/x ?

The integral from 1 to x^2 of (sin(x))/x is \Si(x^2)-0.9460830704

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integral from 1 to x^2 of (sin(x))/x

\int_{1}^{x^{2}} \frac{sin ( x )}{x} d x

Si (x^{2}) - 0.9460830704

Solution steps

\int_{1}^{x^{2}} \frac{sin ( x )}{x} d x

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (x)]_{1}^{x^{2}}

Compute the boundaries:

Si (x^{2}) - 0.9460830704

= Si (x^{2}) - 0.9460830704

What is the integral from 1 to x^2 of (sin(x))/x ?
The integral from 1 to x^2 of (sin(x))/x is \Si(x^2)-0.9460830704