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Popular Calculus >

integral from-2 to 1 of (3x+4)

Solution

\int_{- 2}^{1} (3 x + 4) d x

Solution

\frac{15}{2}

+1

Decimal

7.5

Solution steps

\int_{- 2}^{1} 3 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} 3 x d x + \int_{- 2}^{1} 4 d x

\int_{- 2}^{1} 3 x d x = - \frac{9}{2}

\int_{- 2}^{1} 4 d x = 12

= - \frac{9}{2} + 12

Simplify

- \frac{9}{2} + 12 : \frac{15}{2}

= \frac{15}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-2 to 1 of (3x+4) ?
The integral from-2 to 1 of (3x+4) is 15/2