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Popular Calculus >

integral from-1 to 0 of (-x-1)

Solution

\int_{- 1}^{0} (- x - 1) d x

Solution

- \frac{1}{2}

+1

Decimal

- 0.5

Solution steps

\int_{- 1}^{0} - x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{0} x d x - \int_{- 1}^{0} 1 d x

\int_{- 1}^{0} x d x = - \frac{1}{2}

\int_{- 1}^{0} 1 d x = 1

= - (- \frac{1}{2}) - 1

Simplify

- (- \frac{1}{2}) - 1 : - \frac{1}{2}

= - \frac{1}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of (-x-1) ?
The integral from-1 to 0 of (-x-1) is -1/2