(\partial)/(\partial x)(3e^{2x}-5ln(y)+7)

Lösung

\frac{\partial}{\partial x} (3 e^{2 x} - 5 ln (y) + 7)

6 e^{2 x}

Schritte zur Lösung

\frac{\partial}{\partial x} (3 e^{2 x} - 5 ln (y) + 7)

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 e^{2 x}) - \frac{\partial}{\partial x} (5 ln (y)) + \frac{\partial}{\partial x} (7)

\frac{\partial}{\partial x} (3 e^{2 x}) = 6 e^{2 x}

\frac{\partial}{\partial x} (5 ln (y)) = 0

\frac{\partial}{\partial x} (7) = 0

= 6 e^{2 x} - 0 + 0

Vereinfache

= 6 e^{2 x}

\int_{2}^{7} x d x

\frac{d y}{d x} = (\frac{3 y + 2}{5 x + 4})^{2}

\int ln (2 x) d x

\frac{\partial}{\partial x} (sin (4 x))

\frac{d}{d x} (\frac{7 x}{x ^{2} + 4})