integral from 0 to 0.1 of 400x

Lösung

\int_{0}^{0.1} 400 x d x

2

Schritte zur Lösung

\int_{0}^{0.1} 400 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 400 \cdot \int_{0}^{0.1} x d x

Wende die Potenzregel an

= 400 [\frac{x ^{2}}{2}]_{0}^{0.1}

Vereinfache

= 400 [0.5 x^{2}]_{0}^{0.1}

Berechne die Grenzen:

0.005

= 400 \cdot 0.005

Vereinfache

= 2

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