en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

integral from 1 to 4 of x^2-x-6

Solution

\int_{1}^{4} x^{2} - x - 6 d x

Solution

- \frac{9}{2}

+1

Decimal

- 4.5

Solution steps

\int_{1}^{4} x^{2} - x - 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x - \int_{1}^{4} x d x - \int_{1}^{4} 6 d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} x d x = \frac{15}{2}

\int_{1}^{4} 6 d x = 18

= 21 - \frac{15}{2} - 18

Simplify

21 - \frac{15}{2} - 18 : - \frac{9}{2}

= - \frac{9}{2}

Graph

Popular Examples

integral from 2 to 3 of (2x)/((x^2+2)^3)

integral from 1 to infinity of 1/(x^q)

integral from 0 to 1 of-xln(x)

integral from 0 to 2 of e^{0.5x}

integral from 2 to 6 of-x^2-8x-12

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of x^2-x-6 ?
The integral from 1 to 4 of x^2-x-6 is -9/2