integral from 1 to x of ln(x)

Lösung

\int_{1}^{x} ln (x) d x

x ln (x) - x + 1

Schritte zur Lösung

\int_{1}^{x} ln (x) d x

Wende die partielle Integration an

= [x ln (x) - \int 1 d x]_{1}^{x}

\int 1 d x = x

= [x ln (x) - x]_{1}^{x}

Berechne die Grenzen:

x ln (x) - x + 1

= x ln (x) - x + 1

\int_{- 1}^{0} 9 x^{2} (2 x^{3} + 5)^{2} d x

\int_{1}^{4} x^{- 5} d x

\int_{- 5}^{0} y + 9 d y

\int_{3}^{6} ∣ x - 4 ∣ d x

\int_{- 6}^{3} ∣ x ∣ d x