integral from-1 to 2 of x^3-4x

Lösung

\int_{- 1}^{2} x^{3} - 4 x d x

- \frac{9}{4}

Dezimale

- 2.25

Schritte zur Lösung

\int_{- 1}^{2} x^{3} - 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{3} d x - \int_{- 1}^{2} 4 x d x

\int_{- 1}^{2} x^{3} d x = \frac{15}{4}

\int_{- 1}^{2} 4 x d x = 6

= \frac{15}{4} - 6

Vereinfache

\frac{15}{4} - 6 : - \frac{9}{4}

= - \frac{9}{4}

\int_{1}^{4} 2^{3 x} d x

\int_{- 7}^{7} \frac{t ^{3}}{11 + 8 t ^{2}} d t

\int_{- 7}^{7} 7^{2} - x^{2} d x

\int_{1}^{x} (2 - x) d x

\int_{1}^{4} x x d x