What is the integral from 1 to 2 of sin(x^2) ?

The integral from 1 to 2 of sin(x^2) is sqrt(pi/2)\S(sqrt(2/pi)*2)-sqrt(pi/2)\S(sqrt(2/pi)*1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 2 of sin(x^2)

\int_{1}^{2} sin (x^{2}) d x

\frac{π}{2} § (\frac{2}{π} \cdot 2) - \frac{π}{2} § (\frac{2}{π} \cdot 1)

Solution steps

\int_{1}^{2} sin (x^{2}) d x

Use the nonelementary integral:

\int sin (x^{2}) d x = \frac{π}{2} § (\frac{2}{π} x)

= [\frac{π}{2} § (\frac{2}{π} x)]_{1}^{2}

Compute the boundaries:

\frac{π}{2} § (\frac{2}{π} \cdot 2) - \frac{π}{2} § (\frac{2}{π} \cdot 1)

= \frac{π}{2} § (\frac{2}{π} \cdot 2) - \frac{π}{2} § (\frac{2}{π} \cdot 1)

What is the integral from 1 to 2 of sin(x^2) ?
The integral from 1 to 2 of sin(x^2) is sqrt(pi/2)\S(sqrt(2/pi)*2)-sqrt(pi/2)\S(sqrt(2/pi)*1)