What is the integral from 0 to 2 of 2/(x^2+4) ?

The integral from 0 to 2 of 2/(x^2+4) is pi/4

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integral from 0 to 2 of 2/(x^2+4)

\int_{0}^{2} \frac{2}{x ^{2} + 4} d x

\frac{π}{4}

Decimal

0.78539 \dots

Solution steps

\int_{0}^{2} \frac{2}{x ^{2} + 4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{2} \frac{1}{x ^{2} + 4} d x

Apply Integral Substitution

= 2 \cdot \int_{0}^{1} \frac{1}{2 ( u ^{2} + 1 )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int_{0}^{1} \frac{1}{u ^{2} + 1} d u

Use the common integral:

\int \frac{1}{u ^{2} + 1} d u = arctan (u)

= 2 \cdot \frac{1}{2} [arctan (u)]_{0}^{1}

Simplify

2 \cdot \frac{1}{2} [arctan (u)]_{0}^{1} : [arctan (u)]_{0}^{1}

= [arctan (u)]_{0}^{1}

Compute the boundaries:

\frac{π}{4}

= \frac{π}{4}

What is the integral from 0 to 2 of 2/(x^2+4) ?
The integral from 0 to 2 of 2/(x^2+4) is pi/4