integral from 1 to 2 of 8x^3+6/(x^2)

Lösung

\int_{1}^{2} 8 x^{3} + \frac{6}{x ^{2}} d x

33

Schritte zur Lösung

\int_{1}^{2} 8 x^{3} + \frac{6}{x ^{2}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 8 x^{3} d x + \int_{1}^{2} \frac{6}{x ^{2}} d x

\int_{1}^{2} 8 x^{3} d x = 30

\int_{1}^{2} \frac{6}{x ^{2}} d x = 3

= 30 + 3

Vereinfache

= 33

\int_{- 1}^{1} (4 x^{2} - \frac{16}{3}) d x

\int_{a}^{b} (x - a) (x - b) d x

\int_{0}^{\infty} x^{2} ln (x) d x

\int_{- 7}^{7} 7 - ∣ x ∣ d x

\int_{0}^{π} x^{2} ∣ cos (x) ∣ d x