integral from 0 to 1 of cos(3x-3)

Lösung

\int_{0}^{1} cos (3 x - 3) d x

\frac{1}{3} sin (3)

Dezimale

0.04704 \dots

Schritte zur Lösung

\int_{0}^{1} cos (3 x - 3) d x

Wende U-Substitution an

= \int_{- 3}^{0} cos (u) \frac{1}{3} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{- 3}^{0} cos (u) d u

Nutze das gemeinsame Integral :

\int cos (u) d u = sin (u)

= \frac{1}{3} [sin (u)]_{- 3}^{0}

Berechne die Grenzen:

sin (3)

= \frac{1}{3} sin (3)

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