integral from 2 to 5 of 6+cos(x/(10))

Lösung

\int_{2}^{5} 6 + cos (\frac{x}{10}) d x

18 + 10 (sin (\frac{1}{2}) - sin (\frac{1}{5}))

Dezimale

20.80756 \dots

Schritte zur Lösung

\int_{2}^{5} 6 + cos (\frac{x}{10}) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{5} 6 d x + \int_{2}^{5} cos (\frac{x}{10}) d x

\int_{2}^{5} 6 d x = 18

\int_{2}^{5} cos (\frac{x}{10}) d x = 10 (sin (\frac{1}{2}) - sin (\frac{1}{5}))

= 18 + 10 (sin (\frac{1}{2}) - sin (\frac{1}{5}))

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