What is the integral from 0 to 2 of (e+pi) ?

The integral from 0 to 2 of (e+pi) is 2(e+pi)

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integral from 0 to 2 of (e+pi)

\int_{0}^{2} (e + π) d x

2 (e + π)

Decimal

11.71974 \dots

Solution steps

\int_{0}^{2} e + π d x

Integral of a constant:

\int a d x = a x

= [(e + π) x]_{0}^{2}

Compute the boundaries:

2 (e + π)

= 2 (e + π)

What is the integral from 0 to 2 of (e+pi) ?
The integral from 0 to 2 of (e+pi) is 2(e+pi)