en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

integral from-1 to 1 of 2x^2+1

Solution

\int_{- 1}^{1} 2 x^{2} + 1 d x

Solution

\frac{10}{3}

+1

Decimal

3.33333 \dots

Solution steps

\int_{- 1}^{1} 2 x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 2 x^{2} d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} 2 x^{2} d x = \frac{4}{3}

\int_{- 1}^{1} 1 d x = 2

= \frac{4}{3} + 2

Simplify

\frac{4}{3} + 2 : \frac{10}{3}

= \frac{10}{3}

Graph

Popular Examples

integral from 10 to 15 of (10)/(x^2)

integral from 1 to e of (((ln(x))^5)/x)

integral from 0 to 36 of sqrt(x)+10

integral from 0 to 1 of (e^x+3)/(e^x+3x)

integral from-pi/4 to 0 of sec^2(x)

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of 2x^2+1 ?
The integral from-1 to 1 of 2x^2+1 is 10/3