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Popular Calculus >

integral from 0 to 3 of x(9-x^2)

Solution

\int_{0}^{3} x (9 - x^{2}) d x

Solution

\frac{81}{4}

+1

Decimal

20.25

Solution steps

\int_{0}^{3} x (9 - x^{2}) d x

Expand

x (9 - x^{2}) : 9 x - x^{3}

= \int_{0}^{3} 9 x - x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 9 x d x - \int_{0}^{3} x^{3} d x

\int_{0}^{3} 9 x d x = \frac{81}{2}

\int_{0}^{3} x^{3} d x = \frac{81}{4}

= \frac{81}{2} - \frac{81}{4}

Simplify

\frac{81}{2} - \frac{81}{4} : \frac{81}{4}

= \frac{81}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of x(9-x^2) ?
The integral from 0 to 3 of x(9-x^2) is 81/4