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Popular Calculus >

integral from 1 to 2 of (2x-1)

Solution

\int_{1}^{2} (2 x - 1) d x

Solution

2

Solution steps

\int_{1}^{2} 2 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x d x - \int_{1}^{2} 1 d x

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} 1 d x = 1

= 3 - 1

Simplify

= 2

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (2x-1) ?
The integral from 1 to 2 of (2x-1) is 2