What is the integral from 0 to 1 of sec(x) ?

The integral from 0 to 1 of sec(x) is ln(tan(1)+sec(1))

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integral from 0 to 1 of sec(x)

\int_{0}^{1} sec (x) d x

ln (tan (1) + sec (1))

Decimal

1.22619 \dots

Solution steps

\int_{0}^{1} sec (x) d x

Use the common integral:

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= [ln ∣ tan (x) + sec (x) ∣]_{0}^{1}

Compute the boundaries:

ln (tan (1) + sec (1))

= ln (tan (1) + sec (1))

What is the integral from 0 to 1 of sec(x) ?
The integral from 0 to 1 of sec(x) is ln(tan(1)+sec(1))