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Popular Calculus >

integral from 1 to 6 of |3x-9|

Solution

\int_{1}^{6} ∣ 3 x - 9 ∣ d x

Solution

\frac{39}{2}

+1

Decimal

19.5

Solution steps

\int_{1}^{6} ∣ 3 x - 9 ∣ d x

Eliminate Absolutes

= \int_{1}^{3} - 3 x + 9 d x + \int_{3}^{6} 3 x - 9 d x

\int_{1}^{3} - 3 x + 9 d x = 6

\int_{3}^{6} 3 x - 9 d x = \frac{27}{2}

= 6 + \frac{27}{2}

Simplify

6 + \frac{27}{2} : \frac{39}{2}

= \frac{39}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 6 of |3x-9| ?
The integral from 1 to 6 of |3x-9| is 39/2