What is the integral from 4.6 to 7 of (12x^2-6x+4/x) ?

The integral from 4.6 to 7 of (12x^2-6x+4/x) is 900.81541…

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integral from 4.6 to 7 of (12x^2-6x+4/x)

\int_{4.6}^{7} (12 x^{2} - 6 x + \frac{4}{x}) d x

900.81541 \dots

Solution steps

\int_{4.6}^{7} 12 x^{2} - 6 x + \frac{4}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4.6}^{7} 12 x^{2} d x - \int_{4.6}^{7} 6 x d x + \int_{4.6}^{7} \frac{4}{x} d x

\int_{4.6}^{7} 12 x^{2} d x = 982.656

\int_{4.6}^{7} 6 x d x = 83.52

\int_{4.6}^{7} \frac{4}{x} d x = 1.67941 \dots

= 982.656 - 83.52 + 1.67941 \dots

Simplify

= 900.81541 \dots

What is the integral from 4.6 to 7 of (12x^2-6x+4/x) ?
The integral from 4.6 to 7 of (12x^2-6x+4/x) is 900.81541…