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Popular Calculus >

integral from 0 to 4 of 8x-2x^2

Solution

\int_{0}^{4} 8 x - 2 x^{2} d x

Solution

\frac{64}{3}

+1

Decimal

21.33333 \dots

Solution steps

\int_{0}^{4} 8 x - 2 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 8 x d x - \int_{0}^{4} 2 x^{2} d x

\int_{0}^{4} 8 x d x = 64

\int_{0}^{4} 2 x^{2} d x = \frac{128}{3}

= 64 - \frac{128}{3}

Simplify

64 - \frac{128}{3} : \frac{64}{3}

= \frac{64}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of 8x-2x^2 ?
The integral from 0 to 4 of 8x-2x^2 is 64/3