What is the integral from 1 to 4 of 2^{4x} ?

The integral from 1 to 4 of 2^{4x} is (16380)/(ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 4 of 2^{4x}

\int_{1}^{4} 2^{4 x} d x

\frac{16380}{ln ( 2 )}

Decimal

23631.34476 \dots

Solution steps

\int_{1}^{4} 2^{4 x} d x

Simplify

2^{4 x} : 1 6^{x}

= \int_{1}^{4} 1 6^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{1 6 ^{x}}{ln ( 16 )}]_{1}^{4}

\frac{1 6 ^{x}}{ln ( 16 )} = \frac{2 ^{4 x - 2}}{ln ( 2 )}

= [\frac{2 ^{4 x - 2}}{ln ( 2 )}]_{1}^{4}

Compute the boundaries:

\frac{16380}{ln ( 2 )}

= \frac{16380}{ln ( 2 )}

What is the integral from 1 to 4 of 2^{4x} ?
The integral from 1 to 4 of 2^{4x} is (16380)/(ln(2))