en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

integral from 1 to 2 of-x+2

Solution

\int_{1}^{2} - x + 2 d x

Solution

\frac{1}{2}

+1

Decimal

0.5

Solution steps

\int_{1}^{2} - x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{2} x d x + \int_{1}^{2} 2 d x

\int_{1}^{2} x d x = \frac{3}{2}

\int_{1}^{2} 2 d x = 2

= - \frac{3}{2} + 2

Simplify

- \frac{3}{2} + 2 : \frac{1}{2}

= \frac{1}{2}

Graph

Popular Examples

integral from 3 to infinity of 2e^{-2x}

integral from 0 to 2 of xe^{x/2}

integral from 0 to 1/2 of xln(x)

integral from 0 to 1 of xsqrt(x-1)

integral from 2 to 3 of x^2-2x-3

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of-x+2 ?
The integral from 1 to 2 of-x+2 is 1/2