What is the integral from 0 to 2 of 4x(x^2+3)^3 ?

The integral from 0 to 2 of 4x(x^2+3)^3 is 1160

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integral from 0 to 2 of 4x(x^2+3)^3

\int_{0}^{2} 4 x (x^{2} + 3)^{3} d x

1160

Solution steps

\int_{0}^{2} 4 x (x^{2} + 3)^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{2} x (x^{2} + 3)^{3} d x

Apply u-substitution

= 4 \cdot \int_{3}^{7} \frac{u ^{3}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{2} \cdot \int_{3}^{7} u^{3} d u

Apply the Power Rule

= 4 \cdot \frac{1}{2} [\frac{u ^{4}}{4}]_{3}^{7}

Simplify

4 \cdot \frac{1}{2} [\frac{u ^{4}}{4}]_{3}^{7} : 2 [\frac{u ^{4}}{4}]_{3}^{7}

= 2 [\frac{u ^{4}}{4}]_{3}^{7}

Compute the boundaries:

580

= 2 \cdot 580

Simplify

= 1160

What is the integral from 0 to 2 of 4x(x^2+3)^3 ?
The integral from 0 to 2 of 4x(x^2+3)^3 is 1160