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Popular Calculus >

integral from-1 to 3 of |x|-1

Solution

\int_{- 1}^{3} ∣ x ∣ - 1 d x

Solution

1

Solution steps

\int_{- 1}^{3} ∣ x ∣ - 1 d x

Eliminate Absolutes

= \int_{- 1}^{0} - x - 1 d x + \int_{0}^{3} x - 1 d x

\int_{- 1}^{0} - x - 1 d x = - \frac{1}{2}

\int_{0}^{3} x - 1 d x = \frac{3}{2}

= - \frac{1}{2} + \frac{3}{2}

Simplify

- \frac{1}{2} + \frac{3}{2} : 1

= 1

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 3 of |x|-1 ?
The integral from-1 to 3 of |x|-1 is 1