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Popular Calculus >

integral from 1 to 3 of (x^2-x)

Solution

\int_{1}^{3} (x^{2} - x) d x

Solution

\frac{14}{3}

+1

Decimal

4.66666 \dots

Solution steps

\int_{1}^{3} x^{2} - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{2} d x - \int_{1}^{3} x d x

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} x d x = 4

= \frac{26}{3} - 4

Simplify

\frac{26}{3} - 4 : \frac{14}{3}

= \frac{14}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 3 of (x^2-x) ?
The integral from 1 to 3 of (x^2-x) is 14/3