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Popular Calculus >

integral from 0 to 4 of (8-2x)

Solution

\int_{0}^{4} (8 - 2 x) d x

Solution

16

Solution steps

\int_{0}^{4} 8 - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 8 d x - \int_{0}^{4} 2 x d x

\int_{0}^{4} 8 d x = 32

\int_{0}^{4} 2 x d x = 16

= 32 - 16

Simplify

= 16

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (8-2x) ?
The integral from 0 to 4 of (8-2x) is 16