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Popular Calculus >

integral from 1 to 2 of 3x^2+x

Solution

\int_{1}^{2} 3 x^{2} + x d x

Solution

\frac{17}{2}

+1

Decimal

8.5

Solution steps

\int_{1}^{2} 3 x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 3 x^{2} d x + \int_{1}^{2} x d x

\int_{1}^{2} 3 x^{2} d x = 7

\int_{1}^{2} x d x = \frac{3}{2}

= 7 + \frac{3}{2}

Simplify

7 + \frac{3}{2} : \frac{17}{2}

= \frac{17}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of 3x^2+x ?
The integral from 1 to 2 of 3x^2+x is 17/2