integral from 1 to 2 of ((x^2+4))/x

Lösung

\int_{1}^{2} \frac{( x ^{2} + 4 )}{x} d x

\frac{3}{2} + 4 ln (2)

Dezimale

4.27258 \dots

Schritte zur Lösung

\int_{1}^{2} \frac{x ^{2} + 4}{x} d x

Multipliziere aus

\frac{x ^{2} + 4}{x} : x + \frac{4}{x}

= \int_{1}^{2} x + \frac{4}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x d x + \int_{1}^{2} \frac{4}{x} d x

\int_{1}^{2} x d x = \frac{3}{2}

\int_{1}^{2} \frac{4}{x} d x = 4 ln (2)

= \frac{3}{2} + 4 ln (2)

\int_{1}^{x} \frac{e ^{t}}{t} d t

\int_{0}^{1} (1 - x)^{5} d x

\int_{0}^{1} (1 - y)^{2} d y

\int_{0}^{6 - x} 6 - x - z d z

\int_{0}^{2} (2 x - 1)^{3} d x