integral from 3 to 8 of sqrt(x+1)

Lösung

\int_{3}^{8} x + 1 d x

\frac{38}{3}

Dezimale

12.66666 \dots

Schritte zur Lösung

\int_{3}^{8} x + 1 d x

Wende U-Substitution an

= \int_{4}^{9} u d u

Wende die Potenzregel an

= [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{9}

Berechne die Grenzen:

\frac{38}{3}

= \frac{38}{3}

\int_{- \frac{3 π}{4}}^{0} sin (x) d x

\int_{3}^{- 3} 9 - x^{2} d x

\int_{- 3}^{- 1} \frac{1}{x ^{2}} d x

\int_{0}^{4} y 9 + y^{2} d y

\int_{0}^{1} (x^{\frac{4}{3}} - 2 x^{\frac{1}{3}}) d x