integral from 1 to 2 of e^{1/x} 1/(x^2)

Lösung

\int_{1}^{2} e^{\frac{1}{x}} \frac{1}{x ^{2}} d x

e - e

Dezimale

1.06956 \dots

Schritte zur Lösung

\int_{1}^{2} e^{\frac{1}{x}} \frac{1}{x ^{2}} d x

Wende U-Substitution an

= \int_{1}^{\frac{1}{2}} - e^{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{\frac{1}{2}}^{1} - e^{u} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{\frac{1}{2}}^{1} e^{u} d u)

Nutze das gemeinsame Integral :

\int e^{u} d u = e^{u}

= - (- [e^{u}]_{\frac{1}{2}}^{1})

Vereinfache

= [e^{u}]_{\frac{1}{2}}^{1}

Berechne die Grenzen:

e - e

= e - e

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