What is the integral from 0 to 4 of (3x^2+sqrt(x)) ?

The integral from 0 to 4 of (3x^2+sqrt(x)) is 208/3

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integral from 0 to 4 of (3x^2+sqrt(x))

\int_{0}^{4} (3 x^{2} + x) d x

\frac{208}{3}

Decimal

69.33333 \dots

Solution steps

\int_{0}^{4} 3 x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 3 x^{2} d x + \int_{0}^{4} x d x

\int_{0}^{4} 3 x^{2} d x = 64

\int_{0}^{4} x d x = \frac{16}{3}

= 64 + \frac{16}{3}

Simplify

64 + \frac{16}{3} : \frac{208}{3}

= \frac{208}{3}

What is the integral from 0 to 4 of (3x^2+sqrt(x)) ?
The integral from 0 to 4 of (3x^2+sqrt(x)) is 208/3