What is the integral from 1 to 5 of 2/(x^2) ?

The integral from 1 to 5 of 2/(x^2) is 8/5

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integral from 1 to 5 of 2/(x^2)

\int_{1}^{5} \frac{2}{x ^{2}} d x

\frac{8}{5}

Decimal

1.6

Solution steps

\int_{1}^{5} \frac{2}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{5} \frac{1}{x ^{2}} d x

Apply the Power Rule

= 2 [- \frac{1}{x}]_{1}^{5}

Compute the boundaries:

\frac{4}{5}

= 2 \cdot \frac{4}{5}

Simplify

= \frac{8}{5}

What is the integral from 1 to 5 of 2/(x^2) ?
The integral from 1 to 5 of 2/(x^2) is 8/5