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Popular Calculus >

integral from 0 to 2 of 1-x

Solution

\int_{0}^{2} 1 - x d x

Solution

0

Solution steps

\int_{0}^{2} 1 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 1 d x - \int_{0}^{2} x d x

\int_{0}^{2} 1 d x = 2

\int_{0}^{2} x d x = 2

= 2 - 2

Simplify

= 0

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of 1-x ?
The integral from 0 to 2 of 1-x is 0