integral from 0 to 2 of (3x^2+x-5)

解答

\int_{0}^{2} (3 x^{2} + x - 5) d x

0

求解步骤

\int_{0}^{2} 3 x^{2} + x - 5 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 3 x^{2} d x + \int_{0}^{2} x d x - \int_{0}^{2} 5 d x

\int_{0}^{2} 3 x^{2} d x = 8

\int_{0}^{2} x d x = 2

\int_{0}^{2} 5 d x = 10

= 8 + 2 - 10

化简

= 0

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