What is the integral from 7 to 9 of |f(4x)| ?

The integral from 7 to 9 of |f(4x)| is -64f

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 7 to 9 of |f(4x)|

\int_{7}^{9} ∣ f (4 x) ∣ d x

- 64 f

Solution steps

\int_{7}^{9} ∣ f \cdot 4 x ∣ d x

Eliminate Absolutes

= \int_{7}^{9} - 4 f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 f \cdot \int_{7}^{9} x d x

Apply the Power Rule

= - 4 f [\frac{x ^{2}}{2}]_{7}^{9}

Compute the boundaries:

16

= - 4 f \cdot 16

Simplify

= - 64 f

What is the integral from 7 to 9 of |f(4x)| ?
The integral from 7 to 9 of |f(4x)| is -64f