What is the integral from 0 to 2 of (-x^2-3x) ?

The integral from 0 to 2 of (-x^2-3x) is -26/3

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integral from 0 to 2 of (-x^2-3x)

\int_{0}^{2} (- x^{2} - 3 x) d x

- \frac{26}{3}

Decimal

- 8.66666 \dots

Solution steps

\int_{0}^{2} - x^{2} - 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2} x^{2} d x - \int_{0}^{2} 3 x d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 3 x d x = 6

= - \frac{8}{3} - 6

Simplify

- \frac{8}{3} - 6 : - \frac{26}{3}

= - \frac{26}{3}

What is the integral from 0 to 2 of (-x^2-3x) ?
The integral from 0 to 2 of (-x^2-3x) is -26/3