y^'=(x-14)^2

Lösung

y^{^{'}} = (x - 14)^{2}

y = \frac{x ^{3}}{3} - 14 x^{2} + 196 x + c_{1}

Schritte zur Lösung

y^{'} (x) = (x - 14)^{2}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int (x - 14)^{2} d x

\int (x - 14)^{2} d x = \frac{x ^{3}}{3} - 14 x^{2} + 196 x + c_{1}

y = \frac{x ^{3}}{3} - 14 x^{2} + 196 x + c_{1}

y^{^{''}} + 324 y = sec (18 x), y (0) = 2, y^{^{'}} (0) = - 1

n = 3 \sum \infty \frac{3}{n ^{2} - 3 n + 2}

x \to 0 lim (\frac{( 1 + x ) ^{2}}{x})

\int \frac{( ln ( x ) ) ^{2} + 1}{ln ( x )} d x

y^{^{'}} = \frac{e ^{x - y}}{e ^{x} + 1}