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Popular Calculus >

integral from-1 to 1 of (x^2+x)

Solution

\int_{- 1}^{1} (x^{2} + x) d x

Solution

\frac{2}{3}

+1

Decimal

0.66666 \dots

Solution steps

\int_{- 1}^{1} x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{2} d x + \int_{- 1}^{1} x d x

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} x d x = 0

= \frac{2}{3} + 0

Simplify

= \frac{2}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (x^2+x) ?
The integral from-1 to 1 of (x^2+x) is 2/3