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Popular Calculus >

integral from 0 to 2 of (-2x+4)

Solution

\int_{0}^{2} (- 2 x + 4) d x

Solution

4

Solution steps

\int_{0}^{2} - 2 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2} 2 x d x + \int_{0}^{2} 4 d x

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 4 d x = 8

= - 4 + 8

Simplify

= 4

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (-2x+4) ?
The integral from 0 to 2 of (-2x+4) is 4